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Record W2463954311 · doi:10.1145/3280823

Deterministic Graph Exploration with Advice

2018· preprint· en· W2463954311 on OpenAlex

Why this work is in the frame

A frame that forgets how it found something cannot be audited. These are the routes that admitted this work.

affAt least one author lists a Canadian institution in the pinned OpenAlex snapshot.
fundA Canadian funder is recorded on the work.

Bibliographic record

VenueACM Transactions on Algorithms · 2018
Typepreprint
Languageen
FieldComputer Science
TopicOptimization and Search Problems
Canadian institutionsUniversité du Québec en Outaouais
FundersNatural Sciences and Engineering Research Council of CanadaUniversité du Québec en Outaouais
KeywordsOracleAdvice (programming)GraphComputer scienceTheoretical computer scienceTime complexityCombinatoricsA priori and a posterioriNode (physics)Discrete mathematicsMathematicsAlgorithm

Abstract

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We consider the fundamental task of graph exploration. An n -node graph has unlabeled nodes, and all ports at any node of degree d are arbitrarily numbered 0,…, d −1. A mobile agent, initially situated at some starting node v , has to visit all nodes and stop. The time of the exploration is the number of edge traversals. We consider the problem of how much knowledge the agent has to have a priori , to explore the graph in a given time, using a deterministic algorithm. Following the paradigm of algorithms with advice , this a priori information (advice) is provided to the agent by an oracle , in the form of a binary string, whose length is called the size of advice . We consider two types of oracles. The instance oracle knows the entire instance of the exploration problem, i.e., the port-numbered map of the graph and the starting node of the agent in this map. The map oracle knows the port-numbered map of the graph but does not know the starting node of the agent. What is the minimum size of advice that must be given to the agent by each of these oracles, so that the agent explores the graph in a given time? We first determine the minimum size of advice to achieve exploration in polynomial time. We prove that some advice of size log log log n − c , for any constant c , is sufficient for polynomial exploration, and that no advice of size log log log n −ϕ ( n ), where ϕ is any function diverging to infinity, can help to do this. These results hold both for the instance and for the map oracles. On the other side of the spectrum, when advice is large, there are two natural time thresholds: Θ ( n 2 ) for a map oracle, and Θ ( n ) for an instance oracle. This is because, in both cases, these time benchmarks can be achieved with sufficiently large advice (advice of size O ( n log n ) suffices). We show that, with a map oracle, time Θ ( n 2 ) cannot be improved in general, regardless of the size of advice. What is then the smallest advice to achieve time Θ ( n 2 ) with a map oracle? We show that this smallest size of advice is larger than n δ , for any δ < 1/3. For large advice, the situation changes significantly when we allow an instance oracle instead of a map oracle. In this case, advice of size O ( n log n ) is enough to achieve time O ( n ). Is such a large advice needed to achieve linear time? We answer this question affirmatively. Indeed, we show more: with any advice of size o ( n log n ), the time of exploration must be at least n ϵ , for any ϵ < 2, and with any advice of size O ( n ), the time must be Ω( n 2 ). We finally look at Hamiltonian graphs, as for them it is possible to achieve the absolutely optimal exploration time n −1, when sufficiently large advice (of size o ( n log n )) is given by an instance oracle. We show that a map oracle cannot achieve this: regardless of the size of advice, the time of exploration must be Ω( n 2 ), for some Hamiltonian graphs. However, even for the instance oracle, with advice of size o ( n log n ), optimal time n −1 cannot be achieved: Indeed, we show that the time of exploration with such advice must sometimes exceed the optimal time n −1 by a summand n ϵ , for any ϵ < 1.

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Full frame distilled prediction

Teacher imitation

Not calibrated prevalence, not ground truth. Human validation pending. Learned from the 10,348 direct Codex labels and 10,348 direct Gemma labels. Candidate is the union of thresholded teacher heads; consensus is their intersection. These outputs are machine_predicted_unvalidated and are not human labels or direct frontier model labels.

metaresearch head score (Codex)0.000
metaresearch head score (Gemma)0.000
Version: codex-gemma-dda1882f352aValidation status: machine_predicted_unvalidated
Candidate categoriesMeta-epidemiology (narrow)
Consensus categoriesnone
DomainCandidate signal: none · Consensus signal: none
Study designCandidate signal: Simulation or modeling · Consensus signal: none
GenreCandidate signal: Methods · Consensus signal: Methods
Teacher disagreement score0.711
Threshold uncertainty score1.000

Codex and Gemma teacher scores by category

CategoryCodexGemma
Metaresearch0.0000.000
Meta-epidemiology (narrow)0.0000.000
Meta-epidemiology (broad)0.0000.000
Bibliometrics0.0000.001
Science and technology studies0.0000.000
Scholarly communication0.0000.001
Open science0.0020.000
Research integrity0.0000.001
Insufficient payload (model declined to judge)0.0000.000

Machine scores (provisional)

The two teacher heads of the student model, read on this work. A score orders the frame for review; it never asserts a category, and the validation status ships verbatim with every row.

Baseline scores from an immature model (maturity gate not passed, 7 training rounds). Scores rank; they never assert a category.

Opus teacher head0.044
GPT teacher head0.291
Teacher spread0.247 · how far apart the two teachers sit on this one work
Validation statusscore_only:v0-immature-baseline · verbatim from the scoring run: score_only means the number may rank works, and no category label ships from it